aboutsummaryrefslogtreecommitdiff
path: root/sem4/hpp/m1
diff options
context:
space:
mode:
authorJulian T <julian@jtle.dk>2020-02-05 21:06:10 +0100
committerJulian T <julian@jtle.dk>2020-02-05 21:06:10 +0100
commita362090c5a5c13f422385d69ce7f64fa13c09b9f (patch)
tree48554d5af6fdec2ed115b67c46a822dcbdde51c1 /sem4/hpp/m1
parent41773c52a88ca186df6031248a63dda3c9c29e05 (diff)
Added some exercise solutions
Diffstat (limited to 'sem4/hpp/m1')
-rw-r--r--sem4/hpp/m1/opgaver.md78
1 files changed, 78 insertions, 0 deletions
diff --git a/sem4/hpp/m1/opgaver.md b/sem4/hpp/m1/opgaver.md
new file mode 100644
index 0000000..959eb97
--- /dev/null
+++ b/sem4/hpp/m1/opgaver.md
@@ -0,0 +1,78 @@
+# Opgave 1.3.1
+
+## Del. 2
+
+Ud fra matrix vektor muliplication kan man sige at der ganges N^2 gange.
+
+Også vil man i hver række plus N-1 gang.
+Så der plus'ses `(N-1)*N` gange.
+
+Derfor er der
+
+`2N^2 - N`
+
+Floating point operationer.
+
+## Del. 2
+
+Her vil man bruge output buffer som intermediate variabler.
+
+Derfor vil der være
+
+```
+A x y
+N^2*s + N*s + N*s = (N^2 + 2N) * s
+```
+
+# Opgave 1.3.3
+
+```
+1.
+
+1 3 5
+2 4 6
+
+2.
+
+1 2
+3 4
+5 6
+
+3.
+
+1 4
+2 5
+3 6
+
+4.
+
+1 2 3
+4 5 6
+```
+
+# Opgave 1.3.4
+
+## Del 1.
+
+m er row count B
+
+A * B = C
+
+```
+for column c in B index i:
+ for row r in A index j:
+ i = c' * r // ' means transponere
+ C[j,c] = sum(i)
+ end
+end
+```
+
+# Del 2.
+
+A bliver addresset via kolonner, så det er bedst at bruge column major.
+
+B bliver via rows så det er bedst at bruge row major.
+
+# Del 3.
+Yes because we multiply vektors together.
+