From 890ad2bcee172ab2a4cbb319145f5b42ba38619a Mon Sep 17 00:00:00 2001 From: Julian T Date: Thu, 25 Nov 2021 08:47:19 +0100 Subject: Add notes and assignment solution --- sem7/db/lec5.org | 42 ++++++++++++++++++++++++++++++++++++++++++ sem7/db/lec_xpath.md | 41 +++++++++++++++++++++++++++++++++++++++++ 2 files changed, 83 insertions(+) create mode 100644 sem7/db/lec5.org create mode 100644 sem7/db/lec_xpath.md (limited to 'sem7/db') diff --git a/sem7/db/lec5.org b/sem7/db/lec5.org new file mode 100644 index 0000000..6696a50 --- /dev/null +++ b/sem7/db/lec5.org @@ -0,0 +1,42 @@ +* Opgave 8.3 fra bogen + + #+begin_quote + Consider the parallel hash join algorithm in Sect. 8.4.1.2. + Explain what the build phase and probe phase are. + Is the algorithm symmetric with respect to its input relations? + #+end_quote + +** Explain build and probe phases + + The build phase hashes the =R= phase into $p$ partitions. + Then it sends the partitions to their respective nodes. + The nodes in $[1, p]$ each receive the partitions and creates a local hash table for $R_j$. + + In the probe phase all nodes do the same with =S= and + the nodes $[1, p]$ receives the partitions of =S= joins it with =R=. + +** Is the algorithm symmetric? + + No it's not, be inner join(thus =R=) in the build phase, must be completely stored and hashed. + It can't start doing join on it while it's receiving. + + A symmetric algorithms allows changing the order in which inputs are consumed. + +* Opgave 8.7 fra bogen + + #+begin_quote + Consider a nine way join (ten relations are to be joined), + calculate the number of possible right-deep, left-deep, and bushy trees, + assuming that each relation can be joined with anyone else. + What do you conclude about parallel optimization? + #+end_quote + + With right-deep we can join them in $10!$ different ways, as we just order them differently down the spine. + The same for left-deep. + + For bushy trees we look at the leafs of the tree. + Here we can have $10!$ different orders again. + But we multiply this with the number of ways to create a 5 leaf binary tree, which i count as 3. + + Therefore the end result is $2 * 10! + 3 * 10! = 5 * 10! = 18144000$. + Hmm that does not seem right. diff --git a/sem7/db/lec_xpath.md b/sem7/db/lec_xpath.md new file mode 100644 index 0000000..e28bd94 --- /dev/null +++ b/sem7/db/lec_xpath.md @@ -0,0 +1,41 @@ + +Xpath is used for quering information in XML documents. +Can also be used with postgresql databases. + +When using xpath, we query an abstact document structure. +This is also represented by a nodetree. + +NOTE that `/, /something/else` in the slides are two different queries. + +# Nodetree + +**Document node** is the root of the tree, thus the whole element. +Will often contain document metadata, and will point at a single root element. + +**Element** element represent nodes. + +# Location Step + +Stuff between two `/`'s. +Looks like `${axis}::${node test}[${predicate_1}][${predicate_2}]` + +Axis will default to `child`. +But there are many other, which also have abbreviations. + +# Funktioner og Expressions + +Man kan køre funktioner såsom concat. +Og de kan bruge queries. + +``` +concat("hej", /med/dig/text()) +``` + +# Spørgsmål + +Vil det her give root element flere gange. +``` +//course/.. +``` + +Nope det er sets, den vil ikke være der flere gange. -- cgit v1.2.3